type 12 comparison coding & decoding Practice Questions Answers Test with Solutions & More Shortcuts

Directions:

Read the following information to answer the questions that follow.

In the following questions, two Column I and II have been given. In Column I, few words are given and in Column II, their codes have been given using a particular rule. The order of the smaller letter have been placed in jumbled up form.

You have to decode the language and choose the alternative which is equal to the letter asked in the question.

Column I Column II
(1) DESIGN (A) uklbjz
(2) INFORM (B) cbxkqy
(3) MOTHER (C) ygzwxc
(4) RIGHTS (D) bjucgw
(5) TAILOR (E) wcpybv
(6) GARDEN (F) vzcjlk

Question : 6

What is the code for the letter F?

a) g

b) i

c) b

d) q

Answer: (d)

In the statement (ii), it is clear that the word has a letter F in it, which is not contained by any other word.

Similarly, its code has letter q, which is not contained by any other code.

Hence, F stands for q.

Question : 7

What is the code for the letter G?

a) j

b) i

c) p

d) b

Answer: (a)

We have already found in sol. 10 that G = j.

Question : 8

What is the code for the letter N?

a) k

b) c

c) g

d) u

Answer: (a)

In statements (i) and (ii), common letters are I and N and common codes are b and k.

Therefore, it is clear that IN stands for bk but not necessarily in the same order. From statement (vi), it is clear that the word has letter N and code k is given for it.

Hence, code for N is k. 

Question : 9

What is the code for the letter O?

a) k

b) c

c) y

d) v

Answer: (c)

From statements (iii) and (v),

it is clear that TOR = ywc.

From statements (ii), OR = yc.

From statement (vi), R = c.

Hence, O = y.

Question : 10

What is the code for the letter S?

a) x

b) u

c) z

d) w

Answer: (b)

From statements (i) and (iv),

it is clear that SIG = ubj.

From statement (i), we have already found that

I = b.

Therefore, SG = uj.

Now, from statement (vi), G = j,

therefore S = u.

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